Old 28-01-2008, 05:30 PM
  post #1
အသင္း၀င္ေန႔စြဲ: Nov 2007
တည္ေနရာ: korea
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ပို႔စ္ 28 ခုအတြက္ 73 ဦးမွ ေက်းဇူးတင္ေၾကာင္းေျပာပါသည္။
mmmaung is on a distinguished road
Using Variables In Perl Regular Expressions

I am assuming from now on that you are familiar with substitution operator in perl: s///. A basic example:
$str =~ s/apple/orange/;
would replace the word "apple" with the word "orange". The separator "/" we used in this example can be replaced with any other non alpha-numeric character. The catch is; you have to escape the separator character inside your regular expression. So it is a better idea to use a less common character as a separator than "/". I prefer using "!" as a separator, because it is less common in strings and visually it is a good separator. So same regular expression could be written as:
$str =~ s!apple!orange!;
A common mistake people do when using regular expressions is to try to match a variable in your regular expressions.
$data =~ s!$url!http://go4expert.com!;
This is going to work properly most of the time. But sometime it won't behave as expected or you will be experiencing occasional run time errors. For example, if your $url is equal to
the substitution operator is going to fail and exit with an error message.
"/http://yahoo.com/do.cgi?action=go++&tell=perl/: nested *?+ in regex..."
The reason for the failure is that you can't use "++" inside your regular expression. You have to escape them. The variable might include several special variables, which have to be escaped properly. To correct way to implement this substitution is:
$temp = quotemeta($url);
   $data =~ s!$temp!http://yahoo.com!;
quotemeta() is a standard perl function and it escapes all non-alphanumeric characters in your variable.

ဘ၀ကို ေပါ့ေပါ့ေလး နဲ႕ ပါးပါးေလး ၿဖတ္ခ်င္တယ္:23::23::11:

Last edited by mmmaung; 28-01-2008 at 05:32 PM..
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